What are the solutions to the equation (z+3)^2=-36 ?

The solutions to the equation (z+3)^2=-36 are z=6i-3,z=-6i-3

Find the zeros of (z+3)^2=-36

The zeros of (z+3)^2=-36 are z=6i-3,z=-6i-3

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(z + 3)^{2} = - 36

z = 6 i - 3, z = - 6 i - 3

Solution steps

(z + 3)^{2} = - 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 3 = - 36 : z = 6 i - 3

Solve

z + 3 = - - 36 : z = - 6 i - 3

The solutions to the quadratic equation are:

z = 6 i - 3, z = - 6 i - 3

\frac{8 + i}{3 + 10 i}

- 3 y^{2} - 3 y + 1 = 0

2 x + 3 = 17

(\frac{1}{17})^{- 2}

5 x + 17 \geq 37

What are the solutions to the equation (z+3)^2=-36 ?
The solutions to the equation (z+3)^2=-36 are z=6i-3,z=-6i-3
Find the zeros of (z+3)^2=-36
The zeros of (z+3)^2=-36 are z=6i-3,z=-6i-3