What is the answer to log_{6}(4x^2)-log_{6}(x)=2 ?

The answer to log_{6}(4x^2)-log_{6}(x)=2 is x=9

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log_{6}(4x^2)-log_{6}(x)=2

lo g_{6} (4 x^{2}) - lo g_{6} (x) = 2

x = 9

Solution steps

lo g_{6} (4 x^{2}) - lo g_{6} (x) = 2

Apply log rules

x = 9

Verify Solutions:

x = 9

True

The solution is

x = 9

ln (x) = - 7

3 (lo g_{3} (x) + lo g_{x} (3)) = 10

lo g_{3} (x + 9) = 1

ln (x) - 3 = ln (2)

2 lo g_{7} (5) = lo g_{7} (x)

What is the answer to log_{6}(4x^2)-log_{6}(x)=2 ?
The answer to log_{6}(4x^2)-log_{6}(x)=2 is x=9
Solve for x: log_{6}(4x^2)-log_{6}(x)=2
The solution is x=9