What is the answer to log_{2}(1+log_{3}(1-2x))=2 ?

The answer to log_{2}(1+log_{3}(1-2x))=2 is x=-13

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log_{2}(1+log_{3}(1-2x))=2

lo g_{2} (1 + lo g_{3} (1 - 2 x)) = 2

x = - 13

Solution steps

lo g_{2} (1 + lo g_{3} (1 - 2 x)) = 2

Apply log rules

1 - 2 x = 27

Solve

1 - 2 x = 27 : x = - 13

x = - 13

Verify Solutions:

x = - 13

True

The solution is

x = - 13

lo g_{64} (x) = \frac{2}{3}

0.22 = ln (y)

lo g_{b} (27) = 3

4.5 = - lo g_{10} (x)

ln (x - 2) - ln (x) = 3

What is the answer to log_{2}(1+log_{3}(1-2x))=2 ?
The answer to log_{2}(1+log_{3}(1-2x))=2 is x=-13
Solve for x: log_{2}(1+log_{3}(1-2x))=2
The solution is x=-13