What is the answer to 4ln(2x-1)+3=11 ?

The answer to 4ln(2x-1)+3=11 is x=(e^2+1)/2

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4ln(2x-1)+3=11

4 ln (2 x - 1) + 3 = 11

x = \frac{e ^{2} + 1}{2}

Decimal Notation

x = 4.19452 \dots

Solution steps

4 ln (2 x - 1) + 3 = 11

Move

3

to the right side

4 ln (2 x - 1) = 8

Divide both sides by

4

ln (2 x - 1) = 2

Apply log rules

2 x - 1 = e^{2}

Solve

2 x - 1 = e^{2} : x = \frac{e ^{2} + 1}{2}

x = \frac{e ^{2} + 1}{2}

Verify Solutions:

x = \frac{e ^{2} + 1}{2}

True

The solution is

x = \frac{e ^{2} + 1}{2}

lo g_{2} (- 5 x + 9) = 2

lo g_{10} (x) = 0.9

8 x^{2} = 64 x lo g_{10} (x)

3 + 2 lo g_{2} (x) = lo g_{2} (3 - 10 x)

lo g_{x} (243) = \frac{5}{6}

What is the answer to 4ln(2x-1)+3=11 ?
The answer to 4ln(2x-1)+3=11 is x=(e^2+1)/2
Solve for x: 4ln(2x-1)+3=11
The solution is x=(e^2+1)/2