What is the answer to 4log_{10}(3-2x)=-1 ?

The answer to 4log_{10}(3-2x)=-1 is x=(-1+3\sqrt[4]{10})/(2\sqrt[4]{10)}

Solve for x: 4log_{10}(3-2x)=-1

The solution is x=(-1+3\sqrt[4]{10})/(2\sqrt[4]{10)}

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4 lo g_{10} (3 - 2 x) = - 1

Decimal Notation

x = 1.21882 \dots

Solution steps

4 lo g_{10} (3 - 2 x) = - 1

Divide both sides by

4

lo g_{10} (3 - 2 x) = - \frac{1}{4}

Apply log rules

Solve

Verify Solutions:

True

The solution is

lo g_{2} (lo g_{2} (x)) = 4

x, lo g_{4} (x y) = - 2

lo g_{3} (lo g_{5} (x)) = 1

2 ln (x) + 3 = 4

ln (x + 12) + ln (x - 4) = 2 ln (x)

What is the answer to 4log_{10}(3-2x)=-1 ?
The answer to 4log_{10}(3-2x)=-1 is x=(-1+3\sqrt[4]{10})/(2\sqrt[4]{10)}
Solve for x: 4log_{10}(3-2x)=-1
The solution is x=(-1+3\sqrt[4]{10})/(2\sqrt[4]{10)}