What is the answer to log_{5}(x+1)+log_{5}(x-3)=1 ?

The answer to log_{5}(x+1)+log_{5}(x-3)=1 is x=4

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log_{5}(x+1)+log_{5}(x-3)=1

lo g_{5} (x + 1) + lo g_{5} (x - 3) = 1

x = 4

Solution steps

lo g_{5} (x + 1) + lo g_{5} (x - 3) = 1

Apply log rules

(x + 1) (x - 3) = 5

Solve

(x + 1) (x - 3) = 5 : x = 4, x = - 2

x = 4, x = - 2

Verify Solutions:

x = 4

True

, x = - 2

False

The solution is

x = 4

lo g_{\frac{1}{4}} (x) = 3

4 = lo g_{b} (10000)

ln (\frac{1}{y}) = - ln (y)

0.87 = lo g_{10} (x)

lo g_{2} (n) = 1000000

What is the answer to log_{5}(x+1)+log_{5}(x-3)=1 ?
The answer to log_{5}(x+1)+log_{5}(x-3)=1 is x=4
Solve for x: log_{5}(x+1)+log_{5}(x-3)=1
The solution is x=4