What is the answer to ln(2x)-ln(x-1)=15 ?

The answer to ln(2x)-ln(x-1)=15 is x=(e^{15})/(e^{15)-2}

Solve for x: ln(2x)-ln(x-1)=15

The solution is x=(e^{15})/(e^{15)-2}

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ln (2 x) - ln (x - 1) = 15

x = \frac{e ^{15}}{e ^{15} - 2}

Decimal Notation

x = 1.00000 \dots

Solution steps

ln (2 x) - ln (x - 1) = 15

Add

ln (x - 1)

to both sides

ln (2 x) - ln (x - 1) + ln (x - 1) = 15 + ln (x - 1)

Simplify

ln (2 x) = 15 + ln (x - 1)

Apply log rules

2 x = e^{15} (x - 1)

Solve

2 x = e^{15} (x - 1) : x = \frac{e ^{15}}{e ^{15} - 2}

x = \frac{e ^{15}}{e ^{15} - 2}

Verify Solutions:

x = \frac{e ^{15}}{e ^{15} - 2}

True

The solution is

x = \frac{e ^{15}}{e ^{15} - 2}

ln (x) + ln (x + 3) = ln (10)

lo g_{2} (\frac{y}{3}) = 4

lo g_{9} (x + 4) - lo g_{9} (x) = 2

ln (\frac{t - 66}{125}) = - 0.07 t

lo g_{\frac{1}{6}} (x) = - 1

What is the answer to ln(2x)-ln(x-1)=15 ?
The answer to ln(2x)-ln(x-1)=15 is x=(e^{15})/(e^{15)-2}
Solve for x: ln(2x)-ln(x-1)=15
The solution is x=(e^{15})/(e^{15)-2}