What is the answer to log_{2}(x)+log_{3}(x)=8 ?

The answer to log_{2}(x)+log_{3}(x)=8 is x=3^{(8log_{3}(2))/(1+log_{3)(2)}}

Solve for x: log_{2}(x)+log_{3}(x)=8

The solution is x=3^{(8log_{3}(2))/(1+log_{3)(2)}}

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lo g_{2} (x) + lo g_{3} (x) = 8

x = 3^{\frac{8 l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

Decimal Notation

x = 29.96439 \dots

Solution steps

lo g_{2} (x) + lo g_{3} (x) = 8

Apply log rules

x = 3^{\frac{8 l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

Verify Solutions:

x = 3^{\frac{8 l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

True

The solution is

x = 3^{\frac{8 l o g _{3} ( 2 )}{1 + l o g _{3} ( 2 )}}

ln (3 x - 12) = 2

10 lo g_{10} (3 x) = 30

ln (x + 3) + ln (x) = 1

lo g_{3} (x - a) = b

2.5 = lo g_{10} (x)

What is the answer to log_{2}(x)+log_{3}(x)=8 ?
The answer to log_{2}(x)+log_{3}(x)=8 is x=3^{(8log_{3}(2))/(1+log_{3)(2)}}
Solve for x: log_{2}(x)+log_{3}(x)=8
The solution is x=3^{(8log_{3}(2))/(1+log_{3)(2)}}