What are the solutions to the equation x^2+11x-7=0 ?

The solutions to the equation x^2+11x-7=0 are x=(-11+sqrt(149))/2 ,x=(-11-sqrt(149))/2

Find the zeros of x^2+11x-7=0

The zeros of x^2+11x-7=0 are x=(-11+sqrt(149))/2 ,x=(-11-sqrt(149))/2

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x^{2} + 11 x - 7 = 0

x = \frac{- 11 + 149}{2}, x = \frac{- 11 - 149}{2}

Solution steps

x^{2} + 11 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 7) = 149

x_{1, 2} = \frac{- 11 \pm 149}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 11 + 149}{2 \cdot 1}, x_{2} = \frac{- 11 - 149}{2 \cdot 1}

x = \frac{- 11 + 149}{2 \cdot 1} : \frac{- 11 + 149}{2}

x = \frac{- 11 - 149}{2 \cdot 1} : \frac{- 11 - 149}{2}

The solutions to the quadratic equation are:

x = \frac{- 11 + 149}{2}, x = \frac{- 11 - 149}{2}

7 x - 12 x - 5 = - 45 + 15

4 x^{2} - 17 x + 4 = 0

0 \leq y \leq 1

\frac{7}{10} - \frac{2}{15}

∣ 2 x - 3 ∣ = - 10

What are the solutions to the equation x^2+11x-7=0 ?
The solutions to the equation x^2+11x-7=0 are x=(-11+sqrt(149))/2 ,x=(-11-sqrt(149))/2
Find the zeros of x^2+11x-7=0
The zeros of x^2+11x-7=0 are x=(-11+sqrt(149))/2 ,x=(-11-sqrt(149))/2