What is the answer to 2log_{3}(x)+log_{3}(a)=0 ?

The answer to 2log_{3}(x)+log_{3}(a)=0 is x=3^{-(log_{3}(a))/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2log_{3}(x)+log_{3}(a)=0

2 lo g_{3} (x) + lo g_{3} (a) = 0

x = 3^{- \frac{l o g _{3} ( a )}{2}}

Solution steps

2 lo g_{3} (x) + lo g_{3} (a) = 0

Move

lo g_{3} (a)

to the right side

2 lo g_{3} (x) = - lo g_{3} (a)

Divide both sides by

2

lo g_{3} (x) = - \frac{lo g _{3} ( a )}{2}

Apply log rules

x = 3^{- \frac{l o g _{3} ( a )}{2}}

Verify Solutions:

x = 3^{- \frac{l o g _{3} ( a )}{2}}

True

The solution is

x = 3^{- \frac{l o g _{3} ( a )}{2}}

(ln (x))^{2} - 2 ln (x) - 3 = 0

x, ln (x) = ln (y) + c

lo g_{10} (x + 9) - lo g_{10} (x) = 3

lo g_{x^{3}} (64) = \frac{2}{3}

ln (x) = \infty

What is the answer to 2log_{3}(x)+log_{3}(a)=0 ?
The answer to 2log_{3}(x)+log_{3}(a)=0 is x=3^{-(log_{3}(a))/2}