What is the answer to log_{b}(b^2)=2 ?

The answer to log_{b}(b^2)=2 is 0 1

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log_{b}(b^2)=2

lo g_{b} (b^{2}) = 2

0 < b < 1 or b > 1

Solution steps

lo g_{b} (b^{2}) = 2

Apply log rules

\frac{ln ( b ^{2} )}{ln ( b )} = 2

Multiply both sides by

ln (b)

\frac{ln ( b ^{2} )}{ln ( b )} ln (b) = 2 ln (b)

Simplify

ln (b^{2}) = 2 ln (b)

Apply log rules

b = b

Both sides are equal

True for all b

Verify Solutions:

0 < b < 1 or b > 1

The solution is

0 < b < 1 or b > 1

x, ln (x - y) = 0

0.61 = lo g_{10} (x)

3 lo g_{10} (2 x) = 4

5 lo g_{3} (x) - 12 lo g_{9} (27) = 7

lo g_{9} (x) = (lo g_{3} (x))^{2}

What is the answer to log_{b}(b^2)=2 ?
The answer to log_{b}(b^2)=2 is 0<b<1\lor b>1
Solve for b: log_{b}(b^2)=2
The solution is 0<b<1\lor b>1