What is the answer to log_{3}((x+3)/(x-1))=1 ?

The answer to log_{3}((x+3)/(x-1))=1 is x=3

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log_{3}((x+3)/(x-1))=1

lo g_{3} (\frac{x + 3}{x - 1}) = 1

x = 3

Solution steps

lo g_{3} (\frac{x + 3}{x - 1}) = 1

Apply log rules

\frac{x + 3}{x - 1} = 3^{1}

Multiply both sides by

x - 1

\frac{x + 3}{x - 1} (x - 1) = 3^{1} (x - 1)

Simplify

x + 3 = 3 (x - 1)

Solve

x + 3 = 3 (x - 1) : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

lo g_{3} (x + 4) + lo g_{3} (4 x - 7) = 3

0.81 = lo g_{10} (x)

lo g_{2} (3 \cdot 2^{x} - 4) = 2 x - 1

ln (4 x^{2}) + ln (x) = ln (32)

3 lo g_{10} (x) - 2 = 10

What is the answer to log_{3}((x+3)/(x-1))=1 ?
The answer to log_{3}((x+3)/(x-1))=1 is x=3
Solve for x: log_{3}((x+3)/(x-1))=1
The solution is x=3