What is the answer to log_{4}(-x)+log_{4}(x+10)=2 ?

The answer to log_{4}(-x)+log_{4}(x+10)=2 is x=-8,x=-2

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log_{4}(-x)+log_{4}(x+10)=2

lo g_{4} (- x) + lo g_{4} (x + 10) = 2

x = - 8, x = - 2

Solution steps

lo g_{4} (- x) + lo g_{4} (x + 10) = 2

Apply log rules

- x (x + 10) = 16

Solve

- x (x + 10) = 16 : x = - 8, x = - 2

x = - 8, x = - 2

Verify Solutions:

x = - 8

True

, x = - 2

True

The solutions are

x = - 8, x = - 2

lo g_{10} (x^{2} - 15 x) = 2

lo g_{2} (\frac{x}{6}) = 8

ln (3 x - 15) = 9

lo g_{5} (y) = - 2

(ln (x))^{2} = 2 ln (x)

What is the answer to log_{4}(-x)+log_{4}(x+10)=2 ?
The answer to log_{4}(-x)+log_{4}(x+10)=2 is x=-8,x=-2
Solve for x: log_{4}(-x)+log_{4}(x+10)=2
The solution is x=-8,x=-2