What is the answer to log_{2}(2x-3)+log_{2}(x+6)=3 ?

The answer to log_{2}(2x-3)+log_{2}(x+6)=3 is x=2

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log_{2}(2x-3)+log_{2}(x+6)=3

lo g_{2} (2 x - 3) + lo g_{2} (x + 6) = 3

x = 2

Solution steps

lo g_{2} (2 x - 3) + lo g_{2} (x + 6) = 3

Apply log rules

(2 x - 3) (x + 6) = 8

Solve

(2 x - 3) (x + 6) = 8 : x = 2, x = - \frac{13}{2}

x = 2, x = - \frac{13}{2}

Verify Solutions:

x = 2

True

, x = - \frac{13}{2}

False

The solution is

x = 2

0 = 20 lo g_{10} (w)

lo g_{3} (2 x + 1) + lo g_{3} (x) = 1

lo g_{2} (x) + lo g_{2} (x + 4) = 5

9 - 7 lo g_{10} (8 a + 7) = 2

lo g_{x} (2 x + 3) = 2

What is the answer to log_{2}(2x-3)+log_{2}(x+6)=3 ?
The answer to log_{2}(2x-3)+log_{2}(x+6)=3 is x=2
Solve for x: log_{2}(2x-3)+log_{2}(x+6)=3
The solution is x=2