What is the answer to log_{x-1}(3-x)=2 ?

The answer to log_{x-1}(3-x)=2 is No Solution for x\in\mathbb{R}

Solve for x: log_{x-1}(3-x)=2

The solution is No Solution for x\in\mathbb{R}

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lo g_{x - 1} (3 - x) = 2

No Solution for x \in R

Solution steps

lo g_{x - 1} (3 - x) = 2

Apply log rules

\frac{ln ( 3 - x )}{ln ( x - 1 )} = 2

Multiply both sides by

ln (x - 1)

\frac{ln ( 3 - x )}{ln ( x - 1 )} ln (x - 1) = 2 ln (x - 1)

Simplify

ln (3 - x) = 2 ln (x - 1)

Apply log rules

3 - x = (x - 1)^{2}

Solve

3 - x = (x - 1)^{2} : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

False

, x = - 1

False

The solution is

No Solution for x \in R

lo g_{x} (5) = \frac{1}{5}

lo g_{3} (x - 5) + lo g_{3} (x + 5) = 2

- 8 + lo g_{5} (x + 4) = - 6

x, ln (x^{2} + y^{2}) = 0

0.82 = ln (x)

What is the answer to log_{x-1}(3-x)=2 ?
The answer to log_{x-1}(3-x)=2 is No Solution for x\in\mathbb{R}
Solve for x: log_{x-1}(3-x)=2
The solution is No Solution for x\in\mathbb{R}