What is the answer to log_{4}(2)-log_{4}(y)=1 ?

The answer to log_{4}(2)-log_{4}(y)=1 is y= 1/2

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log_{4}(2)-log_{4}(y)=1

lo g_{4} (2) - lo g_{4} (y) = 1

y = \frac{1}{2}

Decimal Notation

y = 0.5

Solution steps

lo g_{4} (2) - lo g_{4} (y) = 1

Move

lo g_{4} (2)

to the right side

- lo g_{4} (y) = 1 - lo g_{4} (2)

Divide both sides by

- 1

lo g_{4} (y) = - 1 + lo g_{4} (2)

Apply log rules

y = 4^{- 1 + \frac{1}{2}}

Solve

y = 4^{- 1 + \frac{1}{2}} : y = \frac{1}{2}

y = \frac{1}{2}

Verify Solutions:

y = \frac{1}{2}

True

The solution is

y = \frac{1}{2}

lo g_{5} (3 x + 7) = 2

lo g_{10} (x + 6) = 1

lo g_{3} (4 x) = 1 - 2 x

lo g_{\frac{5}{2}} (x) = 3

ln (x) = ln (5) + ln (9)

What is the answer to log_{4}(2)-log_{4}(y)=1 ?
The answer to log_{4}(2)-log_{4}(y)=1 is y= 1/2
Solve for y: log_{4}(2)-log_{4}(y)=1
The solution is y= 1/2