What is the answer to log_{10}(1/(2x+3))=-2 ?

The answer to log_{10}(1/(2x+3))=-2 is x= 97/2

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log_{10}(1/(2x+3))=-2

lo g_{10} (\frac{1}{2 x + 3}) = - 2

x = \frac{97}{2}

Decimal Notation

x = 48.5

Solution steps

lo g_{10} (\frac{1}{2 x + 3}) = - 2

Apply log rules

\frac{1}{2 x + 3} = 1 0^{- 2}

Multiply both sides by

2 x + 3

\frac{1}{2 x + 3} (2 x + 3) = 1 0^{- 2} (2 x + 3)

Simplify

1 0^{- 2} (2 x + 3) : \frac{1}{100} (2 x + 3)

1 = \frac{1}{100} (2 x + 3)

Solve

1 = \frac{1}{100} (2 x + 3) : x = \frac{97}{2}

x = \frac{97}{2}

Verify Solutions:

x = \frac{97}{2}

True

The solution is

x = \frac{97}{2}

lo g_{6} (x + 3) + lo g_{6} (x - 2) = 1

0.43 = lo g_{10} (x)

ln (x + 5) + ln (3 x - 1) = 6 ln (2)

lo g_{0.2} (x) = - 3

x = 8 lo g_{2} (x)

What is the answer to log_{10}(1/(2x+3))=-2 ?
The answer to log_{10}(1/(2x+3))=-2 is x= 97/2
Solve for x: log_{10}(1/(2x+3))=-2
The solution is x= 97/2