What is the answer to log_{2}(3x-1)+log_{2}(x)=1 ?

The answer to log_{2}(3x-1)+log_{2}(x)=1 is x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(3x-1)+log_{2}(x)=1

lo g_{2} (3 x - 1) + lo g_{2} (x) = 1

x = 1

Solution steps

lo g_{2} (3 x - 1) + lo g_{2} (x) = 1

Apply log rules

(3 x - 1) x = 2

Solve

(3 x - 1) x = 2 : x = 1, x = - \frac{2}{3}

x = 1, x = - \frac{2}{3}

Verify Solutions:

x = 1

True

, x = - \frac{2}{3}

False

The solution is

x = 1

ln (2 x - 7) = 0.5

lo g_{2} (x) = 24

lo g_{2} (x) + lo g_{2} (x + 7) = 3

lo g_{2} (x) = 32

ln (x) + ln (x + 30) = ln (31)

What is the answer to log_{2}(3x-1)+log_{2}(x)=1 ?
The answer to log_{2}(3x-1)+log_{2}(x)=1 is x=1
Solve for x: log_{2}(3x-1)+log_{2}(x)=1
The solution is x=1