What is factor (\frac{z^2+20z+96)/(2z+3)}{(z+8)^2} ?

The solution to factor (\frac{z^2+20z+96)/(2z+3)}{(z+8)^2} is (z+12)/((2z+3)(z+8))

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factor (\frac{z^2+20z+96)/(2z+3)}{(z+8)^2}

factor

\frac{\frac{z ^{2} + 20 z + 96}{2 z + 3}}{( z + 8 ) ^{2}}

\frac{z + 12}{( 2 z + 3 ) ( z + 8 )}

Solution steps

\frac{\frac{z ^{2} + 20 z + 96}{2 z + 3}}{( z + 8 ) ^{2}}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{z ^{2} + 20 z + 96}{( 2 z + 3 ) ( z + 8 ) ^{2}}

Factor

z^{2} + 20 z + 96 : (z + 8) (z + 12)

= \frac{( z + 8 ) ( z + 12 )}{( 2 z + 3 ) ( z + 8 ) ^{2}}

Cancel the common factor:

z + 8

= \frac{z + 12}{( 2 z + 3 ) ( z + 8 )}

125 + (x - y)^{3}

13 \geq 2 x - 3 \geq 5

y^{3} - 5 y^{2} + 6 y - 30

(x - 6)^{2} = - 7

1 + [\frac{7}{9} n - 3] < - 4

What is factor (\frac{z^2+20z+96)/(2z+3)}{(z+8)^2} ?
The solution to factor (\frac{z^2+20z+96)/(2z+3)}{(z+8)^2} is (z+12)/((2z+3)(z+8))