What is the answer to log_{5}(3-2x)=log_{5}(-3x) ?

The answer to log_{5}(3-2x)=log_{5}(-3x) is x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{5}(3-2x)=log_{5}(-3x)

lo g_{5} (3 - 2 x) = lo g_{5} (- 3 x)

x = - 3

Solution steps

lo g_{5} (3 - 2 x) = lo g_{5} (- 3 x)

Apply log rules

3 - 2 x = - 3 x

Solve

3 - 2 x = - 3 x : x = - 3

x = - 3

Verify Solutions:

x = - 3

True

The solution is

x = - 3

lo g_{10} (\frac{10 x}{3}) = 2

ln (5 x) = 2

ln (3 x - 17) = 5

ln (x - 6) + 2 ln (x) - ln (x - 30) = 0

lo g_{4} (5 x) = 2

What is the answer to log_{5}(3-2x)=log_{5}(-3x) ?
The answer to log_{5}(3-2x)=log_{5}(-3x) is x=-3
Solve for x: log_{5}(3-2x)=log_{5}(-3x)
The solution is x=-3