What is the answer to log_{10}(x^2-9x)=1 ?

The answer to log_{10}(x^2-9x)=1 is x=10,x=-1

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log_{10}(x^2-9x)=1

lo g_{10} (x^{2} - 9 x) = 1

x = 10, x = - 1

Solution steps

lo g_{10} (x^{2} - 9 x) = 1

Apply log rules

x^{2} - 9 x = 10

Solve

x^{2} - 9 x = 10 : x = 10, x = - 1

x = 10, x = - 1

lo g_{2} (x) = 1000000

3 + 7 \cdot lo g_{5} (x) = 25

0 = ln (x + 1)

ln (x - 8) + ln (x + 1) = ln (x - 24)

lo g_{10} (2 x) = 4.5

What is the answer to log_{10}(x^2-9x)=1 ?
The answer to log_{10}(x^2-9x)=1 is x=10,x=-1
Solve for x: log_{10}(x^2-9x)=1
The solution is x=10,x=-1