What is the answer to log_{2}(x+3)+log_{2}(x+5)=3 ?

The answer to log_{2}(x+3)+log_{2}(x+5)=3 is x=-1

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log_{2}(x+3)+log_{2}(x+5)=3

lo g_{2} (x + 3) + lo g_{2} (x + 5) = 3

x = - 1

Solution steps

lo g_{2} (x + 3) + lo g_{2} (x + 5) = 3

Apply log rules

(x + 3) (x + 5) = 8

Solve

(x + 3) (x + 5) = 8 : x = - 1, x = - 7

x = - 1, x = - 7

Verify Solutions:

x = - 1

True

, x = - 7

False

The solution is

x = - 1

lo g_{e} (x + 2) - lo g_{e} (3 x) = 0

lo g_{10} (9 x) + lo g_{10} (3 x) = 3

lo g_{2 x} (81) = \frac{4}{3}

lo g_{10} (x) = - 4.67

lo g_{10} (x) - lo g_{10} (x - 1) = 1

What is the answer to log_{2}(x+3)+log_{2}(x+5)=3 ?
The answer to log_{2}(x+3)+log_{2}(x+5)=3 is x=-1
Solve for x: log_{2}(x+3)+log_{2}(x+5)=3
The solution is x=-1