What is the answer to log_{10}(9x)+log_{10}(3x)=3 ?

The answer to log_{10}(9x)+log_{10}(3x)=3 is x=10^{(3-3log_{10}(3))/2}

Solve for x: log_{10}(9x)+log_{10}(3x)=3

The solution is x=10^{(3-3log_{10}(3))/2}

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lo g_{10} (9 x) + lo g_{10} (3 x) = 3

x = 1 0^{\frac{3 - 3 l o g _{10} ( 3 )}{2}}

Decimal Notation

x = 6.08580 \dots

Solution steps

lo g_{10} (9 x) + lo g_{10} (3 x) = 3

Apply log rules

x = 1 0^{\frac{3 - 3 l o g _{10} ( 3 )}{2}}

Verify Solutions:

x = 1 0^{\frac{3 - 3 l o g _{10} ( 3 )}{2}}

True

The solution is

x = 1 0^{\frac{3 - 3 l o g _{10} ( 3 )}{2}}

lo g_{2 x} (81) = \frac{4}{3}

lo g_{10} (x) = - 4.67

lo g_{10} (x) - lo g_{10} (x - 1) = 1

ln (x + 4) = 1

lo g_{6} (8 x) - 3 lo g_{6} (3) = 0

What is the answer to log_{10}(9x)+log_{10}(3x)=3 ?
The answer to log_{10}(9x)+log_{10}(3x)=3 is x=10^{(3-3log_{10}(3))/2}
Solve for x: log_{10}(9x)+log_{10}(3x)=3
The solution is x=10^{(3-3log_{10}(3))/2}