What is the answer to solvefor x,ln(y)=ln(x)+C ?

The answer to solvefor x,ln(y)=ln(x)+C is x=e^{-C}y

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solvefor x,ln(y)=ln(x)+C

solve for

x, ln (y) = ln (x) + C

x = e^{- C} y

Solution steps

ln (y) = ln (x) + C

Switch sides

ln (x) + C = ln (y)

Move

C

to the right side

ln (x) = ln (y) - C

Apply log rules

x = e^{- C} y

ln (x + 8) + ln (x - 2) = 2 ln (x)

x, lo g_{10} (x) = 0.3293

y, ln (5 y) = x

ln (2 x^{2} + 7) = 9

ln (e + x) = 1

What is the answer to solvefor x,ln(y)=ln(x)+C ?
The answer to solvefor x,ln(y)=ln(x)+C is x=e^{-C}y