What is the answer to log_{2}(x)+log_{2}(4x)=2 ?

The answer to log_{2}(x)+log_{2}(4x)=2 is x=1

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log_{2}(x)+log_{2}(4x)=2

lo g_{2} (x) + lo g_{2} (4 x) = 2

x = 1

Solution steps

lo g_{2} (x) + lo g_{2} (4 x) = 2

Apply log rules

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

lo g_{x} (3) = lo g_{3} (9) x^{3}

lo g_{10} (x^{2} + 4 x - 2) = 1

lo g_{4} (x) + 4 lo g_{x} (4) = 5

lo g_{4} (x^{2} + 5 x - 8) = 2

lo g_{x} (24) = 5

What is the answer to log_{2}(x)+log_{2}(4x)=2 ?
The answer to log_{2}(x)+log_{2}(4x)=2 is x=1
Solve for x: log_{2}(x)+log_{2}(4x)=2
The solution is x=1