What is the answer to log_{2}(x+1)-log_{4}(x-3)=2 ?

The answer to log_{2}(x+1)-log_{4}(x-3)=2 is x=7

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log_{2}(x+1)-log_{4}(x-3)=2

lo g_{2} (x + 1) - lo g_{4} (x - 3) = 2

x = 7

Solution steps

lo g_{2} (x + 1) - lo g_{4} (x - 3) = 2

Apply log rules

(x + 1)^{2} = 16 (x - 3)

Solve

(x + 1)^{2} = 16 (x - 3) : x = 7

x = 7

Verify Solutions:

x = 7

True

The solution is

x = 7

lo g_{x} (3) = - 2

lo g_{2} (4 x - 3) = 1

0.41 = ln (y)

ln (\frac{t ^{2}}{2}) = 10

3 ln (x) = 5 x - 6

What is the answer to log_{2}(x+1)-log_{4}(x-3)=2 ?
The answer to log_{2}(x+1)-log_{4}(x-3)=2 is x=7
Solve for x: log_{2}(x+1)-log_{4}(x-3)=2
The solution is x=7