What is the answer to log_{2}(x)-16log_{10}(x)=-63 ?

The answer to log_{2}(x)-16log_{10}(x)=-63 is x= 1/(10^{(63log_{10)(2))/(1-16log_{10)(2)}}}

Solve for x: log_{2}(x)-16log_{10}(x)=-63

The solution is x= 1/(10^{(63log_{10)(2))/(1-16log_{10)(2)}}}

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lo g_{2} (x) - 16 lo g_{10} (x) = - 63

x = \frac{1}{1 0 ^{\frac{63 l o g _{10} ( 2 )}{1 - 16 l o g _{10} ( 2 )}}}

Decimal Notation

x = 93155.79287 \dots

Solution steps

lo g_{2} (x) - 16 lo g_{10} (x) = - 63

Apply log rules

x = \frac{1}{1 0 ^{\frac{63 l o g _{10} ( 2 )}{1 - 16 l o g _{10} ( 2 )}}}

Verify Solutions:

x = \frac{1}{1 0 ^{\frac{63 l o g _{10} ( 2 )}{1 - 16 l o g _{10} ( 2 )}}}

True

The solution is

x = \frac{1}{1 0 ^{\frac{63 l o g _{10} ( 2 )}{1 - 16 l o g _{10} ( 2 )}}}

lo g_{b} (4) = 2

ln (x) = - 6

lo g_{10} (x) + lo g_{10} (x + 4) = 2

ln (x - 1) = 3

ln (6 x + 4) = 3

What is the answer to log_{2}(x)-16log_{10}(x)=-63 ?
The answer to log_{2}(x)-16log_{10}(x)=-63 is x= 1/(10^{(63log_{10)(2))/(1-16log_{10)(2)}}}
Solve for x: log_{2}(x)-16log_{10}(x)=-63
The solution is x= 1/(10^{(63log_{10)(2))/(1-16log_{10)(2)}}}