What is the answer to log_{3}(x+5)+log_{3}(x-1)=3 ?

The answer to log_{3}(x+5)+log_{3}(x-1)=3 is x=4

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log_{3}(x+5)+log_{3}(x-1)=3

lo g_{3} (x + 5) + lo g_{3} (x - 1) = 3

x = 4

Solution steps

lo g_{3} (x + 5) + lo g_{3} (x - 1) = 3

Apply log rules

(x + 5) (x - 1) = 27

Solve

(x + 5) (x - 1) = 27 : x = 4, x = - 8

x = 4, x = - 8

Verify Solutions:

x = 4

True

, x = - 8

False

The solution is

x = 4

0.34 = lo g_{10} (x)

lo g_{2} (x) + lo g_{2} (5) = 6

lo g_{2} (5 x - 16) = 2

x^{0.5 l o g_{10} (x)} = 0.01 x^{2}

x, z = ln (2 x + 3 y)

What is the answer to log_{3}(x+5)+log_{3}(x-1)=3 ?
The answer to log_{3}(x+5)+log_{3}(x-1)=3 is x=4
Solve for x: log_{3}(x+5)+log_{3}(x-1)=3
The solution is x=4