What is the answer to log_{6}(2x-5)=log_{4}(6) ?

The answer to log_{6}(2x-5)=log_{4}(6) is x=(6^{log_{4}(6)}+5)/2

Solve for x: log_{6}(2x-5)=log_{4}(6)

The solution is x=(6^{log_{4}(6)}+5)/2

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lo g_{6} (2 x - 5) = lo g_{4} (6)

x = \frac{6 ^{l o g_{4} (6)} + 5}{2}

Decimal Notation

x = 7.56659 \dots

Solution steps

lo g_{6} (2 x - 5) = lo g_{4} (6)

Apply log rules

2 x - 5 = 6^{l o g_{4} (6)}

Solve

2 x - 5 = 6^{l o g_{4} (6)} : x = \frac{6 ^{l o g_{4} (6)} + 5}{2}

x = \frac{6 ^{l o g_{4} (6)} + 5}{2}

6 ln (2) - ln (4) = - ln (x)

lo g_{2} (lo g_{2} (x)) = 1

lo g_{x} (2 x - 3) = 1

lo g_{10} (x^{2}) = 6

lo g_{2} (3 x - 5) = 3

What is the answer to log_{6}(2x-5)=log_{4}(6) ?
The answer to log_{6}(2x-5)=log_{4}(6) is x=(6^{log_{4}(6)}+5)/2
Solve for x: log_{6}(2x-5)=log_{4}(6)
The solution is x=(6^{log_{4}(6)}+5)/2