What is the answer to x+log_{10}(x-9)=1 ?

The answer to x+log_{10}(x-9)=1 is x=(\W_{0}(\frac{ln(10))/(100000000))}{ln(10)}+9

Solve for x: x+log_{10}(x-9)=1

The solution is x=(\W_{0}(\frac{ln(10))/(100000000))}{ln(10)}+9

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x + lo g_{10} (x - 9) = 1

x = \frac{W _{0} ( \frac{l n ( 10 )}{100000000} )}{ln ( 10 )} + 9

Decimal Notation

x = 9.00000001

Solution steps

x + lo g_{10} (x - 9) = 1

Move

x

to the right side

lo g_{10} (x - 9) = 1 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{l o g_{10} (x - 9)} = 1 0^{1 - x}

Simplify

1 0^{l o g_{10} (x - 9)} : x - 9

x - 9 = 1 0^{1 - x}

Solve

x - 9 = 1 0^{1 - x} : x = \frac{W _{0} ( \frac{l n ( 10 )}{100000000} )}{ln ( 10 )} + 9

x = \frac{W _{0} ( \frac{l n ( 10 )}{100000000} )}{ln ( 10 )} + 9

Verify Solutions:

x = \frac{W _{0} ( \frac{l n ( 10 )}{100000000} )}{ln ( 10 )} + 9

True

The solution is

x = \frac{W _{0} ( \frac{l n ( 10 )}{100000000} )}{ln ( 10 )} + 9

lo g_{6} (x) + lo g_{6} (x + 16) = 2

lo g_{10} (2 x + 1) = lo g_{10} (x + 6)

ln (5 x - 3) = ln (2 x)

lo g_{b} (3125) = - 5

0.59 = ln (y)

What is the answer to x+log_{10}(x-9)=1 ?
The answer to x+log_{10}(x-9)=1 is x=(\W_{0}(\frac{ln(10))/(100000000))}{ln(10)}+9
Solve for x: x+log_{10}(x-9)=1
The solution is x=(\W_{0}(\frac{ln(10))/(100000000))}{ln(10)}+9