What is the answer to log_{9}(8-x)+log_{9}(8-x)=1 ?

The answer to log_{9}(8-x)+log_{9}(8-x)=1 is x=5

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log_{9}(8-x)+log_{9}(8-x)=1

lo g_{9} (8 - x) + lo g_{9} (8 - x) = 1

x = 5

Solution steps

lo g_{9} (8 - x) + lo g_{9} (8 - x) = 1

Add similar elements:

lo g_{9} (8 - x) + lo g_{9} (8 - x) = 2 lo g_{9} (8 - x)

2 lo g_{9} (8 - x) = 1

Divide both sides by

2

lo g_{9} (8 - x) = \frac{1}{2}

Apply log rules

8 - x = 3

Solve

8 - x = 3 : x = 5

x = 5

Verify Solutions:

x = 5

True

The solution is

x = 5

ln (x^{2}) - 1 = 3

lo g_{\frac{1}{2}} (- x + 5) = 2

0.456 = ln (x^{3})

lo g_{10} (5 x - 1) = 0.6

ln (3 x - 16) = 8

What is the answer to log_{9}(8-x)+log_{9}(8-x)=1 ?
The answer to log_{9}(8-x)+log_{9}(8-x)=1 is x=5
Solve for x: log_{9}(8-x)+log_{9}(8-x)=1
The solution is x=5