What is the answer to 2log_{4}(x-2)+1=7 ?

The answer to 2log_{4}(x-2)+1=7 is x=66

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2log_{4}(x-2)+1=7

2 lo g_{4} (x - 2) + 1 = 7

x = 66

Solution steps

2 lo g_{4} (x - 2) + 1 = 7

Move

1

to the right side

2 lo g_{4} (x - 2) = 6

Divide both sides by

2

lo g_{4} (x - 2) = 3

Apply log rules

x - 2 = 64

Solve

x - 2 = 64 : x = 66

x = 66

Verify Solutions:

x = 66

True

The solution is

x = 66

lo g_{25} (x) = - 1.5

lo g_{6} (x - 3) + lo g_{6} (x + 2) = 1

lo g_{10} (2 x) = 0

2 ln (x + 3) - ln (x + 1) = 3 ln (2)

ln (x + 8) + ln (x - 3) = 2 ln (x)

What is the answer to 2log_{4}(x-2)+1=7 ?
The answer to 2log_{4}(x-2)+1=7 is x=66
Solve for x: 2log_{4}(x-2)+1=7
The solution is x=66