What is the answer to log_{3}(3x^2)+log_{3}(3)=2 ?

The answer to log_{3}(3x^2)+log_{3}(3)=2 is x=1,x=-1

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log_{3}(3x^2)+log_{3}(3)=2

lo g_{3} (3 x^{2}) + lo g_{3} (3) = 2

x = 1, x = - 1

Solution steps

lo g_{3} (3 x^{2}) + lo g_{3} (3) = 2

Move

lo g_{3} (3)

to the right side

lo g_{3} (3 x^{2}) = 2 - lo g_{3} (3)

Apply log rules

3 x^{2} = 3

Solve

3 x^{2} = 3 : x = 1, x = - 1

x = 1, x = - 1

Verify Solutions:

x = 1

True

, x = - 1

True

The solutions are

x = 1, x = - 1

lo g_{3} (x + 7) = lo g_{3} (2 x - 1)

lo g_{10} (x) - lo g_{10} (x + 1) = - 1

3 ln (5 x + 1) - 8 = 4

ln (5 x + 4) = 6

ln (x + 3) + ln (x) = 4

What is the answer to log_{3}(3x^2)+log_{3}(3)=2 ?
The answer to log_{3}(3x^2)+log_{3}(3)=2 is x=1,x=-1
Solve for x: log_{3}(3x^2)+log_{3}(3)=2
The solution is x=1,x=-1