What is the answer to ln(3x+4)-ln(4x+2)=ln(3x+2) ?

The answer to ln(3x+4)-ln(4x+2)=ln(3x+2) is x=0

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ln(3x+4)-ln(4x+2)=ln(3x+2)

ln (3 x + 4) - ln (4 x + 2) = ln (3 x + 2)

x = 0

Solution steps

ln (3 x + 4) - ln (4 x + 2) = ln (3 x + 2)

Add

ln (4 x + 2)

to both sides

ln (3 x + 4) - ln (4 x + 2) + ln (4 x + 2) = ln (3 x + 2) + ln (4 x + 2)

Simplify

ln (3 x + 4) = ln (3 x + 2) + ln (4 x + 2)

Apply log rules

3 x + 4 = (3 x + 2) (4 x + 2)

Solve

3 x + 4 = (3 x + 2) (4 x + 2) : x = 0, x = - \frac{11}{12}

x = 0, x = - \frac{11}{12}

Verify Solutions:

x = 0

True

, x = - \frac{11}{12}

False

The solution is

x = 0

lo g_{2} (x) = x

lo g_{10} (x) - 8 lo g_{10} (2 x) = 0

lo g_{3} (x - 5) = 2

lo g_{3} (x) = lo g_{3} (7)

ln (w) = n

What is the answer to ln(3x+4)-ln(4x+2)=ln(3x+2) ?
The answer to ln(3x+4)-ln(4x+2)=ln(3x+2) is x=0
Solve for x: ln(3x+4)-ln(4x+2)=ln(3x+2)
The solution is x=0