What is the answer to nlog_{a}(x)=log_{a}(x^n) ?

The answer to nlog_{a}(x)=log_{a}(x^n) is True for all x

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nlog_{a}(x)=log_{a}(x^n)

n lo g_{a} (x) = lo g_{a} (x^{n})

True for all x

Solution steps

n lo g_{a} (x) = lo g_{a} (x^{n})

Apply log rules

n lo g_{a} (x) = n lo g_{a} (x)

Rewrite the equation with

lo g_{a} (x) = u

n u = n u

Both sides are equal

True for all u

True for all x

lo g_{2} ((r + 13)^{2}) = 6

- lo g_{10} (x) = 10

lo g_{4} (6 x) - 3 lo g_{4} (5) = 1

lo g_{2} (x + 3) = 1

2 ln (2 x) = 1 + ln (a)

What is the answer to nlog_{a}(x)=log_{a}(x^n) ?
The answer to nlog_{a}(x)=log_{a}(x^n) is True for all x