What is the answer to 4ln(2x+9)+5=29 ?

The answer to 4ln(2x+9)+5=29 is x=(e^6-9)/2

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4ln(2x+9)+5=29

4 ln (2 x + 9) + 5 = 29

x = \frac{e ^{6} - 9}{2}

Decimal Notation

x = 197.21439 \dots

Solution steps

4 ln (2 x + 9) + 5 = 29

Move

5

to the right side

4 ln (2 x + 9) = 24

Divide both sides by

4

ln (2 x + 9) = 6

Apply log rules

2 x + 9 = e^{6}

Solve

2 x + 9 = e^{6} : x = \frac{e ^{6} - 9}{2}

x = \frac{e ^{6} - 9}{2}

Verify Solutions:

x = \frac{e ^{6} - 9}{2}

True

The solution is

x = \frac{e ^{6} - 9}{2}

lo g_{x} (9 x - 20) = 2

x, ln (x^{2}) = 4

ln (4 x - 1) - 3 ln (9) = 2 ln (3)

lo g_{3} (25 - x^{2}) = 2

ln (a) = 8 ln (9) - 12 ln (3)

What is the answer to 4ln(2x+9)+5=29 ?
The answer to 4ln(2x+9)+5=29 is x=(e^6-9)/2
Solve for x: 4ln(2x+9)+5=29
The solution is x=(e^6-9)/2