What is the answer to log_{6}(x-1)+log_{6}(x)=1 ?

The answer to log_{6}(x-1)+log_{6}(x)=1 is x=3

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log_{6}(x-1)+log_{6}(x)=1

lo g_{6} (x - 1) + lo g_{6} (x) = 1

x = 3

Solution steps

lo g_{6} (x - 1) + lo g_{6} (x) = 1

Apply log rules

(x - 1) x = 6

Solve

(x - 1) x = 6 : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions:

x = 3

True

, x = - 2

False

The solution is

x = 3

a = - lo g_{10} (x)

\frac{1}{2} ln (x + 3) - ln (x) = 0

x^{2} ln (x) - 49 ln (x) = 0

y, ln (y) = - x^{2}

x, 3 ln (x) - ln (y) = 4

What is the answer to log_{6}(x-1)+log_{6}(x)=1 ?
The answer to log_{6}(x-1)+log_{6}(x)=1 is x=3
Solve for x: log_{6}(x-1)+log_{6}(x)=1
The solution is x=3