What is the answer to log_{8}(2N-3)=log_{8}(4-N) ?

The answer to log_{8}(2N-3)=log_{8}(4-N) is N= 7/3

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log_{8}(2N-3)=log_{8}(4-N)

lo g_{8} (2 N - 3) = lo g_{8} (4 - N)

N = \frac{7}{3}

Decimal Notation

N = 2.33333 \dots

Solution steps

lo g_{8} (2 N - 3) = lo g_{8} (4 - N)

Apply log rules

2 N - 3 = 4 - N

Solve

2 N - 3 = 4 - N : N = \frac{7}{3}

N = \frac{7}{3}

Verify Solutions:

N = \frac{7}{3}

True

The solution is

N = \frac{7}{3}

5 lo g_{2} (2 x) = 20

ln (x + 10) + ln (x - 4) = 2 ln (x)

2 ln (x - 6) = - 4

ln (x - 5) + ln (5 x + 1) = 10

lo g_{4} (x + 1) + lo g_{4} (x - 1) = 4

What is the answer to log_{8}(2N-3)=log_{8}(4-N) ?
The answer to log_{8}(2N-3)=log_{8}(4-N) is N= 7/3
Solve for N: log_{8}(2N-3)=log_{8}(4-N)
The solution is N= 7/3