What is the answer to log_{2}(39x)-log_{2}(x-5)=4 ?

The answer to log_{2}(39x)-log_{2}(x-5)=4 is No Solution for x\in\mathbb{R}

Solve for x: log_{2}(39x)-log_{2}(x-5)=4

The solution is No Solution for x\in\mathbb{R}

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lo g_{2} (39 x) - lo g_{2} (x - 5) = 4

No Solution for x \in R

Solution steps

lo g_{2} (39 x) - lo g_{2} (x - 5) = 4

Add

lo g_{2} (x - 5)

to both sides

lo g_{2} (39 x) - lo g_{2} (x - 5) + lo g_{2} (x - 5) = 4 + lo g_{2} (x - 5)

Simplify

lo g_{2} (39 x) = 4 + lo g_{2} (x - 5)

Apply log rules

39 x = 16 (x - 5)

Solve

39 x = 16 (x - 5) : x = - \frac{80}{23}

x = - \frac{80}{23}

Verify Solutions:

x = - \frac{80}{23}

False

The solution is

No Solution for x \in R

2 lo g_{10} (x - 1) = 2 x - 5

lo g_{x} (8 x - 3) - lo g_{x} (4) = 2

2 lo g_{8} (x + 2) = lo g_{8} (2 x + 19)

lo g_{5} (x + 5) - lo g_{5} (x - 3) = 1

lo g_{10} (6 x) - 3 = - 4

What is the answer to log_{2}(39x)-log_{2}(x-5)=4 ?
The answer to log_{2}(39x)-log_{2}(x-5)=4 is No Solution for x\in\mathbb{R}
Solve for x: log_{2}(39x)-log_{2}(x-5)=4
The solution is No Solution for x\in\mathbb{R}