What is the answer to ln(-x)+ln(10)=5 ?

The answer to ln(-x)+ln(10)=5 is x=-(e^5)/(10)

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ln(-x)+ln(10)=5

ln (- x) + ln (10) = 5

x = - \frac{e ^{5}}{10}

Decimal Notation

x = - 14.84131 \dots

Solution steps

ln (- x) + ln (10) = 5

Move

ln (10)

to the right side

ln (- x) = 5 - ln (10)

Apply log rules

- x = \frac{e ^{5}}{10}

Solve

- x = \frac{e ^{5}}{10} : x = - \frac{e ^{5}}{10}

x = - \frac{e ^{5}}{10}

Verify Solutions:

x = - \frac{e ^{5}}{10}

True

The solution is

x = - \frac{e ^{5}}{10}

ln (x - 2 e) + ln (x - 3 e) = 2

ln (3 x - 11) = 9

ln (3 x - 11) = 3

lo g_{3} (x) + lo g_{2} (x) = 5

lo g_{2} (3 x - 3) = 4

What is the answer to ln(-x)+ln(10)=5 ?
The answer to ln(-x)+ln(10)=5 is x=-(e^5)/(10)
Solve for x: ln(-x)+ln(10)=5
The solution is x=-(e^5)/(10)