What is the answer to log_{4}(x)+log_{4}(x-15)=2 ?

The answer to log_{4}(x)+log_{4}(x-15)=2 is x=16

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log_{4}(x)+log_{4}(x-15)=2

lo g_{4} (x) + lo g_{4} (x - 15) = 2

x = 16

Solution steps

lo g_{4} (x) + lo g_{4} (x - 15) = 2

Apply log rules

x (x - 15) = 16

Solve

x (x - 15) = 16 : x = 16, x = - 1

x = 16, x = - 1

Verify Solutions:

x = 16

True

, x = - 1

False

The solution is

x = 16

x, lo g_{y} (x) = 2

3 = 20 lo g_{10} (x)

lo g_{5} (p) = 10

lo g_{x} (25) = lo g_{5} (x)

lo g_{2} (a) + lo g_{a} (4) = 3

What is the answer to log_{4}(x)+log_{4}(x-15)=2 ?
The answer to log_{4}(x)+log_{4}(x-15)=2 is x=16
Solve for x: log_{4}(x)+log_{4}(x-15)=2
The solution is x=16