What is the answer to log_{2}(2x)=log_{2}(5x+4)-3 ?

The answer to log_{2}(2x)=log_{2}(5x+4)-3 is x= 4/11

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log_{2}(2x)=log_{2}(5x+4)-3

lo g_{2} (2 x) = lo g_{2} (5 x + 4) - 3

x = \frac{4}{11}

Decimal Notation

x = 0.36363 \dots

Solution steps

lo g_{2} (2 x) = lo g_{2} (5 x + 4) - 3

Apply log rules

16 x = 5 x + 4

Solve

16 x = 5 x + 4 : x = \frac{4}{11}

x = \frac{4}{11}

Verify Solutions:

x = \frac{4}{11}

True

The solution is

x = \frac{4}{11}

ln (x^{7}) - ln (x^{2}) = 5

lo g_{8} (x) = - 1

lo g_{8} (x) = - 3

lo g_{10} (x + 2) + lo g_{10} (5) = 2

ln (x - 3) = 1

What is the answer to log_{2}(2x)=log_{2}(5x+4)-3 ?
The answer to log_{2}(2x)=log_{2}(5x+4)-3 is x= 4/11
Solve for x: log_{2}(2x)=log_{2}(5x+4)-3
The solution is x= 4/11