What is the answer to log_{4}(2x-1)=3 ?

The answer to log_{4}(2x-1)=3 is x= 65/2

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log_{4}(2x-1)=3

lo g_{4} (2 x - 1) = 3

x = \frac{65}{2}

Decimal Notation

x = 32.5

Solution steps

lo g_{4} (2 x - 1) = 3

Apply log rules

2 x - 1 = 64

Solve

2 x - 1 = 64 : x = \frac{65}{2}

x = \frac{65}{2}

lo g_{4} (2 x - 1) = 2

lo g_{2} (x) = 4

lo g_{2} (x) = 6

ln (z) = 2.021

ln (x^{2} + 4) = 2 ln (x) + ln (4)

What is the answer to log_{4}(2x-1)=3 ?
The answer to log_{4}(2x-1)=3 is x= 65/2
Solve for x: log_{4}(2x-1)=3
The solution is x= 65/2