What is the answer to solvefor x,ln(y)=ln(1+x) ?

The answer to solvefor x,ln(y)=ln(1+x) is x=y-1 {y>0}

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solvefor x,ln(y)=ln(1+x)

solve for

x, ln (y) = ln (1 + x)

x = y - 1 {y > 0}

Solution steps

ln (y) = ln (1 + x)

Apply log rules

y = 1 + x

Solve

y = 1 + x : x = y - 1

x = y - 1

Verify Solutions:

x = y - 1 {y > 0}

The solution is

x = y - 1 {y > 0}

0.67 = lo g_{10} (x)

lo g_{10} (x - 15) = lo g_{10} (x)

3 lo g_{2} (2 x) = 3

y, ln (x + y) = x

ln (x - 2) - ln (x) = ln (54)

What is the answer to solvefor x,ln(y)=ln(1+x) ?
The answer to solvefor x,ln(y)=ln(1+x) is x=y-1 {y>0}