What is the answer to log_{10}(2x+4)=1+log_{10}(x) ?

The answer to log_{10}(2x+4)=1+log_{10}(x) is x= 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{10}(2x+4)=1+log_{10}(x)

lo g_{10} (2 x + 4) = 1 + lo g_{10} (x)

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

lo g_{10} (2 x + 4) = 1 + lo g_{10} (x)

Apply log rules

2 x + 4 = 10 x

Solve

2 x + 4 = 10 x : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

ln (x) = 1.5

lo g_{10} (5 x) = 1.7

ln (x) = 2.4

ln (x + 1) = 1 + ln (x - 1)

3 ln (x^{2} - 2) = 2

What is the answer to log_{10}(2x+4)=1+log_{10}(x) ?
The answer to log_{10}(2x+4)=1+log_{10}(x) is x= 1/2
Solve for x: log_{10}(2x+4)=1+log_{10}(x)
The solution is x= 1/2