What are the solutions to the equation x^2-2x+35=0 ?

The solutions to the equation x^2-2x+35=0 are x=1+sqrt(34)i,x=1-sqrt(34)i

Find the zeros of x^2-2x+35=0

The zeros of x^2-2x+35=0 are x=1+sqrt(34)i,x=1-sqrt(34)i

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x^{2} - 2 x + 35 = 0

x = 1 + 34 i, x = 1 - 34 i

Solution steps

x^{2} - 2 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 35 : 234 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 34 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 34 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 34 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 34 i}{2 \cdot 1} : 1 + 34 i

x = \frac{- ( - 2 ) - 2 34 i}{2 \cdot 1} : 1 - 34 i

The solutions to the quadratic equation are:

x = 1 + 34 i, x = 1 - 34 i

2 x^{4} + x^{2} - 6

\frac{3}{11} + \frac{3}{10} + \frac{5}{14}

\frac{3}{2} - 1

4 g - 3 < 7 g + 1

∣ 3 x - 3 ∣ > 12

What are the solutions to the equation x^2-2x+35=0 ?
The solutions to the equation x^2-2x+35=0 are x=1+sqrt(34)i,x=1-sqrt(34)i
Find the zeros of x^2-2x+35=0
The zeros of x^2-2x+35=0 are x=1+sqrt(34)i,x=1-sqrt(34)i