What is the answer to log_{x}(1/2)=-2 ?

The answer to log_{x}(1/2)=-2 is x=e^{(ln(2))/2}

Solve for x: log_{x}(1/2)=-2

The solution is x=e^{(ln(2))/2}

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lo g_{x} (\frac{1}{2}) = - 2

x = e^{\frac{l n ( 2 )}{2}}

Decimal Notation

x = 1.41421 \dots

Solution steps

lo g_{x} (\frac{1}{2}) = - 2

Apply log rules

\frac{ln ( \frac{1}{2} )}{ln ( x )} = - 2

Multiply both sides by

ln (x)

\frac{ln ( \frac{1}{2} )}{ln ( x )} ln (x) = - 2 ln (x)

Apply log rules

x = e^{\frac{l n ( 2 )}{2}}

Verify Solutions:

x = e^{\frac{l n ( 2 )}{2}}

True

The solution is

x = e^{\frac{l n ( 2 )}{2}}

x, lo g_{2} (6 x + 3) = 5

lo g_{x + 5} (4 x) = 3

lo g_{3} (a) = 2

ln (3 x) - ln (x - 4) = ln (x + 3)

x, lo g_{10} (x) = t

What is the answer to log_{x}(1/2)=-2 ?
The answer to log_{x}(1/2)=-2 is x=e^{(ln(2))/2}
Solve for x: log_{x}(1/2)=-2
The solution is x=e^{(ln(2))/2}