What is the answer to log_{3}(3x+2)=log_{3}(4x-6) ?

The answer to log_{3}(3x+2)=log_{3}(4x-6) is x=8

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log_{3}(3x+2)=log_{3}(4x-6)

lo g_{3} (3 x + 2) = lo g_{3} (4 x - 6)

x = 8

Solution steps

lo g_{3} (3 x + 2) = lo g_{3} (4 x - 6)

Apply log rules

3 x + 2 = 4 x - 6

Solve

3 x + 2 = 4 x - 6 : x = 8

x = 8

Verify Solutions:

x = 8

True

The solution is

x = 8

2 = ln (x + 1)

x, ln (x) = y

ln (lo g_{2} (2)) + lo g_{2} (x) = 2

lo g_{x} (16) = \frac{4}{3}

1.25 = 20 \cdot lo g_{10} (v)

What is the answer to log_{3}(3x+2)=log_{3}(4x-6) ?
The answer to log_{3}(3x+2)=log_{3}(4x-6) is x=8
Solve for x: log_{3}(3x+2)=log_{3}(4x-6)
The solution is x=8