What is the answer to -1+log_{11}(7k+10)=-3 ?

The answer to -1+log_{11}(7k+10)=-3 is k=-1209/847

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-1+log_{11}(7k+10)=-3

- 1 + lo g_{11} (7 k + 10) = - 3

k = - \frac{1209}{847}

Decimal Notation

k = - 1.42739 \dots

Solution steps

- 1 + lo g_{11} (7 k + 10) = - 3

Move

1

to the right side

lo g_{11} (7 k + 10) = - 2

Apply log rules

7 k + 10 = \frac{1}{121}

Solve

7 k + 10 = \frac{1}{121} : k = - \frac{1209}{847}

k = - \frac{1209}{847}

Verify Solutions:

k = - \frac{1209}{847}

True

The solution is

k = - \frac{1209}{847}

lo g_{x} (\frac{16}{9}) = 2

lo g_{27} (8 1^{x}) = x - 1

ln (x + 3) - ln (4 - 3 x) = 2 ln (2)

lo g_{10} (x) + lo g_{10} (x + 5) = 9

ln (x) = 3 ln (x)

What is the answer to -1+log_{11}(7k+10)=-3 ?
The answer to -1+log_{11}(7k+10)=-3 is k=-1209/847
Solve for k: -1+log_{11}(7k+10)=-3
The solution is k=-1209/847