What is the answer to ln(x^2-4)=0 ?

The answer to ln(x^2-4)=0 is x=sqrt(5),x=-sqrt(5)

Solve for x: ln(x^2-4)=0

The solution is x=sqrt(5),x=-sqrt(5)

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ln (x^{2} - 4) = 0

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

ln (x^{2} - 4) = 0

Apply log rules

x^{2} - 4 = 1

Solve

x^{2} - 4 = 1 : x = 5, x = - 5

x = 5, x = - 5

ln (x) = 8.699959935

lo g_{3} (5 x - 1) = 4

0.33 = ln (x)

0.33 = ln (y)

\frac{1}{ln ( x + y - 2 )} = 1

What is the answer to ln(x^2-4)=0 ?
The answer to ln(x^2-4)=0 is x=sqrt(5),x=-sqrt(5)
Solve for x: ln(x^2-4)=0
The solution is x=sqrt(5),x=-sqrt(5)